If sum of cubes of first 'm' natural numbers is 441 then sum of first 'm' natural numbers is _____

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Solution

The correct option is C 21
Given, sum of cubes of first 'm' natural numbers is 441.
$∵$ (Sum of first 'n' natural numbers) $^{2}$ =
Sum of cubes of first 'n' natural numbers
$∴$ (sum of first 'm' natural numbers) $^{2}$ = 441
$\Rightarrow$ sum of first 'm' natural numbers = $\sqrt{441}$
= 21

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