If t=4√h32 and t=12, then find the value of h.
228 m
288 m
264 m
338 m
t=4√h32
Squaring both sides we get,
t2=16h32
h=2t2
h=2(t2)
h=288m
The figure shows two positions A and B at the same height h above the ground. If the maximum height of the projectile is H, then determine the time t elapsed between the positions A and B in terms of H.
Add t−t2−14, 15t3+13+9t−8t2, 12t2−19−24t and 4t−9t2+19t3. If t=−1 find the value of the expression. [4 MARKS]