wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If Tm,Tm+n and Tmn are respectively the mth,(m+n)th and (mn)th terms of an AP, then prove that Tm+n+Tmn=2Tm

Open in App
Solution

Given Tn=a+(m1)d

Tm+n=a+(m+n1)d

Tmn=a+(mn1)d

Now Tm+n+Tmn

=a+(m+n1)d+a+(mn1)d

=2a+md+ndd+mdndd

=2a+2mdd

=2[a+(m1)d]=2Tm

Hence Proved

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Arithmetic Progression - Sum of n Terms
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon