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Question

If Tm,Tm+n and Tmn are respectively the mth,(m+n)th and (mn)th terms of an AP, then prove that Tm+n+Tmn=2Tm

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Solution

Given Tn=a+(m1)d

Tm+n=a+(m+n1)d

Tmn=a+(mn1)d

Now Tm+n+Tmn

=a+(m+n1)d+a+(mn1)d

=2a+md+ndd+mdndd

=2a+2mdd

=2[a+(m1)d]=2Tm

Hence Proved

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