Question

If tan $A=\frac{5}{12}$, find the value of $(sinA+cosA)\times$sec A :

• A. $\frac{6}{13}$
• B. $\frac{7}{12}$
• C. $\frac{17}{12}$
• D. $\frac{12}{17}$

Answer 1

The correct option is C $\frac{17}{12}$

$\tan A=\frac{5}{12}$

$\Rightarrow (\sin A+\cos A)\times \sec A=\sin A.\sec A+\cos A.\sec A$

$=\frac{\sin A}{\cos A}+1$

$=\tan A+1$

$=\frac{5}{12}+1$

$=\frac{17}{12}$

Hence, the answer is $=\frac{17}{12}.$