Question

If $tanA=\frac{3}{4}$, then find the value of $\frac{SinA+CosA}{SinA-CosA}$.

• A. -7

Answer 1

The correct option is A -7
Given,
$tanA=\frac{3}{4}$

Now,
$\frac{SinA+CosA}{SinA-CosA}$

Dividing the numerator and denominator by $CosA$

$=\frac{\frac{SinA}{CosA}+1}{\frac{SinA}{CosA}-1}$
$=\frac{tanA+1}{tanA-1}$
$=\frac{\frac{3}{4}+1}{\frac{3}{4}-1}$
$=\frac{\frac{7}{4}}{\frac{-1}{4}}$
$=-7$