Question

If $\tan \theta =\cot ({30}^o+\theta )$, find the value of $\theta$

Answer 1

We can write $tan\theta =\frac{sin\theta }{cos\theta }$ For $\theta ={30}^o$, $tan\theta =\frac{1}{\sqrt{3}}$

$For\theta ={30}^o,cot\theta =\frac{1}{\sqrt{3}}$

Hence value of $\theta ={30}^o$