If tanx=ba, then (a+b)(a-b)+(a-b)(a+b)=?
2sinxsin2x
2cosxcos2x
2cosxsin2x
2sinxcos2x
Explanation for correct option
Given tanx=ba
(a+b)(a-b)+(a-b)(a+b)=(a+b)+(a-b)(a-b)(a+b)=2aa2-b2∵a2-b2=(a-b)(a+b)=2aa1-ba2=21-tan2x∵tanx=ba=21-sin2xcos2x∵tanx=sinxcosx=2cosxcos2x-sin2x=2cosxcos2x∵cos2x=cos2x-sin2x
Hence option (B) is correct i.e. 2cosxcos2x
If ab+ba=1, then a3+b3=
If tan x=ba, then find the value of √a+ba−b+√a−ba+b
If sin θ =ab then cos θ = ?
(a) b√b2−a2(b) √b2−a2b(c) a√b2−a2 (d) ba