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If tan2x =tan...

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If tan2x =tan2/x then the value of x is

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\frac{tan 2^{\circ} \cdot tan 2017^{\circ} \cdot tan 2019^{\circ}}{tan 2019^{\circ} - tan 2017^{\circ} - tan 2^{\circ}} = a

a = tan x,

x

is an acute angle in degree, then the value of

x

0^{0} \leq x \leq 90

1 + {tan}^{2} x - 2 tan x = 0

, then the value of

x

tan (\frac{x}{2}) = c o sec x - sin x

, then the value of

{tan}^{2} (\frac{x}{2})

f (x) = ⎧ ⎪ ⎨ ⎪ ⎩ \begin{matrix} \frac{sin 2 x - tan 2 x}{(e^{x} - 1) x^{2}}, & x \neq 0 k, & x = 0 \end{matrix}

is continuous at

x = 0,

then the absolute value of

k

tan 1^{\circ} tan 1^{\circ} tan 2^{\circ} . . . . . . . . . tan 89^{\circ} = x^{2} - 8,

then the value of

x

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