If ten volumes of dihydrogen gas reacts with five volumes of dioxygen gas, how many volumes of water vapour would be produced?

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Solution

The balanced chemical equation for the reaction is,

$2 H_{2} + O_{2} \to 2 H_{2} O$ .

The volume of a gas is directly proportional to the number of moles.

Thus, 2 volumes of dihydrogen react with 1 volume of oxygen to form 2 volumes of water.

Thus, 10 volumes of dihydrogen react with 5 volume of oxygen to form 10 volumes of water.

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Similar questions

If ten volumes of dihydrogen gas react with five volumes of dioxygen gas, how many volumes of water vapour would be produced?

2 K (s) + 2 H_{2} O (l) \to 2 K O H (a q) + H_{2} (g)

3.0

C O (g) + H_{2} O (g) \to C O_{2} (g) + H_{2} (g); K e q = 1.0

C O

H_{2}

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