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Depression in Freezing Point

If a g of ...

Question

If $a$ g of $K H C_{2} O_{4}$ is used to neutralize $100$ mL of $0.02 M K M n O_{4}$ in acid medium whereas, $b$ g of $K H C_{2} O_{4}$ is used to neutralize $100$ mL of $0.02 M C a {(O H)}_{2}$ , then:

a = b

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4 a = 5 b

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5 a = 4 b

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2 a = b

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Solution

The correct option is B $4 a = 5 b$
Since no. of equivalent of ${K H C}_{2} O_{4}$ $=$ No. of equivalent of ${K M n O}_{4}$
$2 {C O}_{2}$ {n-factor = 2} $∴ \frac{2 a}{E q w t} = (100 \times 0.02 \times 5) \to (1)$
Similarly,
$∵$ (one acidic $- H$ ) $\to n_{f} = 1 {\frac{b}{E q w t} = (100 \times 0.02 \times 2)}$
$∴ \frac{2 a}{b} = \frac{5}{2} ∴ 4 a = 5 b$

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