wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If sec2x2010sin2010xdx=P(x)sin2010x+C, then value of P(π3) is

A
0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
13
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
3
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
None of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 3
sec2x2010sin2010xdx=sec2x(sin x)201020101(sin x)2010dx=I1I2
Applying by parts on I1, we get
I1=tanx(sinx)2010+2010tanx cosx(sinx)2011dx=tanx(sinx)2010+2010dx(sinx)2010I=I1I2=tanx(sinx)2010=P(x)(sinx)2010P(π3)=tanπ3=3

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Integration by Parts
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon