If the activation energies of the forward and backward reactions of a reversible reaction are Ea(f) and Ea(b), respectively. The ΔE of the reaction is ...........
A
Ea(F)−Ea(b)
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B
Ea(F)+Ea(b)
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C
Ea(F)=Ea(b)
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D
−Ea(F)+Ea(b)
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Solution
The correct option is AEa(F)−Ea(b) As we know, ΔE=Ea(F)−Ea(b)