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Question

If the adjoining circuit is connected to a $$250\ volt$$ alternating voltage. The potential different across the $$(i)$$ resistor $$(ii)$$ capacitor.
1020198_ce6e3fcd6546439e8dae8866a9e88211.png


Solution

The impedance is given as,

$$\left| Z \right| = \sqrt {{{\left( {30} \right)}^2} + {{\left( {40} \right)}^2}} $$

$$\left| Z \right| = 50\;\Omega $$

The current in the circuit is given as,

$$V = IZ$$

$$250 = I \times 50$$

$$I = 5\;{\rm{A}}$$

The potential across the resistor is given as,

$${V_R} = IR$$

$${V_R} = 5 \times 40$$

$${V_R} = 200\;{\rm{V}}$$

The potential across the capacitor is given as,

$${V_C} = I{X_C}$$

$${V_C} = 5 \times 30$$

$${V_C} = 150\;{\rm{V}}$$


Physics
NCERT
Standard XII

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