Question

# If the adjoining circuit is connected to a $$250\ volt$$ alternating voltage. The potential different across the $$(i)$$ resistor $$(ii)$$ capacitor.

Solution

## The impedance is given as, $$\left| Z \right| = \sqrt {{{\left( {30} \right)}^2} + {{\left( {40} \right)}^2}}$$ $$\left| Z \right| = 50\;\Omega$$ The current in the circuit is given as, $$V = IZ$$ $$250 = I \times 50$$ $$I = 5\;{\rm{A}}$$ The potential across the resistor is given as, $${V_R} = IR$$ $${V_R} = 5 \times 40$$ $${V_R} = 200\;{\rm{V}}$$ The potential across the capacitor is given as, $${V_C} = I{X_C}$$ $${V_C} = 5 \times 30$$ $${V_C} = 150\;{\rm{V}}$$PhysicsNCERTStandard XII

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