If the air on Earth's surface is replaced with water, then to what extent the water level must rise so as to maintain the same pressure $[10^{5} \frac{N}{m^{2}}]$ on Earth's surface? [Assume nothing above water surface. given g = 10 $m / s^{2}$ , density of water = 1000 $k g / m^{3}$ .

10 m

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5 m

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20 m

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15 m

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Solution

The correct option is A
10 m

We know the Atm pressure = $10^{5} \frac{N}{m^{2}}$ [approx]
If the height of water atmosphere = h
Then, pressure due to water = $ρ$ hg
[Neglecting variation in 'g' and constant density of water]
$ρ$ hg= $10^{5}$
$1000 \times 10 \times h = 10^{5}$
H=10m(approx)

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