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Angle between Pair of Straight Lines

If the angle ...

Question

If the angle between the two lines represented by $2 x^{2} + 5 x y + 3 y^{2} + 6 x + 7 y + 4 = 0$ is ${tan}^{- 1}$ m then m is _______?

\frac{1}{5}

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\frac{1}{7}

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\frac{2}{5}

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\frac{1}{4}

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Solution

The correct option is B $\frac{1}{5}$
$tan θ = \frac{2 \sqrt{(h^{2} - a b)}}{a + b} = \frac{1}{5}$
$∴ θ = {tan}^{- 1} \frac{1}{5}$ .

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Similar questions

If the angle between the two lines represented by $2 x^{2} + 5 x y + 3 y^{2} + 6 x + 7 y + 4 = 0$ is ${tan}^{- 1} m$ , then m =

2 x^{2} + 5 x y + 3 y^{2} + 6 x + 7 y + 4 = 0

{tan}^{- 1} (m),

m

2 x^{2} + 5 x y + 3 y^{2} + 6 x + 7 y + 4 = 0

{tan}^{- 1} (m)

m

2 x^{2} + 5 x y + 3 y^{2} + 7 y + 4 = 0

{tan}^{- 1} m

m

2 x^{2} + 5 x y + 3 y^{2} + 6 x + 7 y + 4 = 0

{tan}^{- 1} (m)

m = \frac{1}{5}

θ

a x^{2} + 2 h x y + b y^{2} + 2 g x + 2 f y + c = 0

{tan}^{- 1} \frac{(2 \sqrt{h^{2} - a b})}{| a + b |}

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