If the area of a circle increases at a uniform rate, than the perimeter will vary
A
inversely as the square of its radius
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B
inversely as the radius
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C
directly as the radius
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D
directly as the square of its radius
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Solution
The correct option is B inversely as the radius A=πr2 dAdt=2πrdrdt ⇒drdt=k2πr (saydAdt=k)
Now, P=2πr ⇒dPdt=2π.drdt =2π×k2πr =kr dPdt∝1r ∴ Perimeter varies inversely as the radius.