Question

If the area of a sector of a circle with radius $6$ cm and angle of the sector is ${60}^o$ is $n\pi$. Find $n$?

Answer 1

Given:

Radius $=6$

Angle of the sector $={60}^{\circ }$

Find the area of the sector.

Area of sector $=\frac{\theta }{360}\pi r^2$

$n\pi =\frac{\theta }{360}\pi r^2$

$n=\frac{60}{360}\times 6\times 6$

$n=6$

Thus, the value of n is 6.