Question

If the area of an equilateral triangle is $25\sqrt{3}$ sq. cms, then find its side.

• A. $10$ cm
• B. $10\sqrt{3}$ cm
• C. $5$ cm
• D. $5\sqrt{3}$ cm

Answer 1

The correct option is A $10$ cm

We know that, the area of equilateral triangle is given by

$A=\frac{\sqrt{3}}{4}{a}^2$, where $a$ is side of triangle

We are given that area of equilateral triangle is $A=25\sqrt{3}sq.cms$.

So, $25\sqrt{3}=\frac{\sqrt{3}}{4}{a}^2$

$a^2=\frac{25\sqrt{3}\times 4}{\sqrt{3}}=100$

$a=10cms$