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Question

# If the area of trapezium ABCE is 35 cm2, and CE = 8 cm, AE = 5 cm, find the area of â–³BDC.

A
5 cm2
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B
6 cm2
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C
10 cm2
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D
12 cm2
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Solution

## The correct option is A 5 cm2Area of triangle = Area of trapezium ABCE - Area of rectangle ABDE Area of trapezium ABCE = 12×(Sum of parallel sides)×height 35 = 12×(AB+CE)×AE 35 = 12×(AB+8)×5 35×25 = AB+8 = 7×2 = 14 AB+8 = 14 AB = 14-8 = 6 cm Area of rectangle ABDE = length×breadth = AB×AE = 6×5 = 30 cm2 Area of triangle = 35 - 30 = 5 cm2

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