If the area of trianlge ABC is 16 cm2, find the area of triangle PRC.(in cm2)
Triangle ABC and Parallelogram ABCP are on the equal base and same parallels.
So, Area(ABCP) = 2 × Area(△ABC) = 32 cm2
Also Area(ABCP) = 2 × Area(△PRC)
Area(△PRC) = 16 cm2