Question

If the Cartesian product A $\times$ A has 16 elements among which few elements are found to be (-1, 0), (0, 1), (1, 2). Find set A.

• A. {-1, 0, 2, 3}
• B. {-1, 0, 1}
• C. {-1, 0, 1, 2}
• D. {0, 1, 2, 3}

Answer 1

The correct option is C

{-1, 0, 1, 2}

Since A $\times$ A has 16 elements

So, A should have 4 elements. Only if A has elements {-1, 0, 1, 2} then A X A can result some elemts as - (-1, 0), (0, 1), (1, 2)

So, four distinct elements in A $\times$ A = {-1, 0, 1, 2}

Therefore, set A = {-1, 0, 1, 2}