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Question

If the chords of the hyperbola x2y2=a2 touch the parabola y2=4ax, then the locus of the midpoints of the chords is the curve

A
y2(x+a)=x3
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B
y2(xa)=x3
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C
y2(x+2a)=3x3
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D
y2(x2a)=2x3
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Solution

The correct option is B y2(xa)=x3
If (x1,y1) is the midpoint of the chord to the hyperbola x2y2=a2,
its equation is T=S1
i.e., xx1yy1a2=x21y21a2
xx1yy1=x21y21
y=x1y1x+y21x21y1

If this is a tangent to y2=4ax,
then c=am
y21x21y1=ay1x1
x31=y21(x1a)
Locus of (x1,y1) is x3=y2(xa)

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