The correct option is B y2(x−a)=x3
If (x1,y1) is the midpoint of the chord to the hyperbola x2−y2=a2,
its equation is T=S1
i.e., xx1−yy1−a2=x21−y21−a2
⇒xx1−yy1=x21−y21
⇒y=x1y1x+y21−x21y1
If this is a tangent to y2=4ax,
then c=am
⇒y21−x21y1=ay1x1
⇒x31=y21(x1−a)
∴ Locus of (x1,y1) is x3=y2(x−a)