If the circle x2-y2-2 g x-2 f y-c-0 touches x-axis- thenA- g2-cB- g-fC- g2-f2-cD- f2-c

The correct option is A Intercept √(g^2 c) = 0 ∴ g^2 = C. ...

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Formation of a Differential Equation from a General Solution

If the circle...

Question

If the circle $x^{2} + y^{2} + 2 g x + 2 f y + c = 0$ touches x-axis, then

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x^{2} + y^{2} + 2 g x + 2 f y + c = 0

(c > 0)

\frac{π}{2},

An equilateral triangle inscribed in the circle $x^{2} + y^{2} + 2 g x + 2 f y + c$ = 0 then its side is

g^{2} < c < f^{2}

x^{2} + y^{2} + 2 g x + 2 f y + c = 0

x^{2} + y^{2} + 2 g x + 2 f y + c = 0

The centre and radius of the circle $x^{2} + y^{2} + 2 g x + 2 y f + c = 0$ are and respectively.

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