If the circles x2+y2−6x−8y−24 = 0 and 3x2+3y2+2gx+2fy+0 = 0 are concentric then (g.f)
(-9,-12)
(-6,-8)
(-3,-4)
(9,12)
x2+y2−6x−8y−24 = 0,centre of the circle= (3,4)
3x2+3y2+2gx+2fy+c = 0 Centre of the circle = (−g3,−f3) (g,f) = (-9,-12)
If (-3, 2) lies on the circle x2+y2+2gx+2fy+c=0 which is concentric with the circle x2+y2+6x+8y−5=0, then c=