Question

If the coefficient of real expansion of a liquid is ${\frac{1}{5500}}^{0}C$. The temperature at which it's density is $1$% less than density at $0^{0}C$ is

• A. 55.5${}^0$C
• B. 100${}^0$C
• C. 99${}^0$C
• D. 1${}^0$C

Answer 1

The correct option is A 55.5${}^0$C

$\frac{d_0}{d_t}=1+{\gamma }_{r}t$
$\frac{d_0}{0.99d_0}=1+{\gamma }_{r}t$
$\Rightarrow \frac{1}{99}=\frac{1}{5500}t$
$\Rightarrow t={55.55}^{0}C$