You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard VI

Mathematics

Conversion of Length, Mass and Capacity

If the combin...

Question

If the combined length of 10 equal rods is 40 cm then the combined length of 5 equal rods is:

15 cm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

20 cm

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

40 cm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

16 cm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B
20 cm

Suggest Corrections

Similar questions

Q. A brass rod of length

40 c m

is joined to a copper rod of length

50 c m

. The two rods are of the same thickness and at an initial temperature of

40^{o} C

. What is the change in length of the combined rod, when the same is heated to

280^{o} C .

Coefficients of linear expansion of brass and copper are

1.9 \times 10^{- 5}^{o} C^{- 1}

and

1.7 \times 10^{- 5}^{o} C^{- 1}

respectively.

Q. Two uniform rods of equal length but of different masses are rigidly combined to form a

L -

shaped body, which is then pivoted about

O

as shown in figure. If combination is in equilibrium then ratio

M / m

will be

Q. A brass rod of length

40 c m

is joined to a copper rod of length

50 c m

. The two rods are of the same thickness and at initial temperature of

40^{\circ} C

. What is the change in length of the combine rod, when the same is heated to

280^{\circ} C

. Coefficients of linear expansion of brass and copper are

1.9 \times 10^{- 5}^{\circ} C^{- 1}

and

1.7 \times 10^{- 5}^{\circ} C^{- 1}

respectively.

Q. Two uniform rods of equal length but of different masses are rigidly combined to form a

L -

shaped body, which is then pivoted about

O

as shown in figure. If combination is in equilibrium then ratio

M / m

will be

Q. A brass rod of length

50 c m

and diameter

3.0 m m

is joined to a steel rod of the same length and diameter. If the change in length of the combined rod at

250^{o} C

is (

A \times 10^{- 2} c m

), given the original lengths are at

{20.0}^{o} C

, what is the sum of digits of

A

?
The ends of the rod are free to expand (Coefficient of linear expansion of brass

= 2.0 \times 10^{- 5} K^{- 1}

, steel

= 1.2 \times 10^{- 5} K^{- 1}

)

Join BYJU'S Learning Program

If the combined length of 10 equal rods is 40 cm then the combined length of 5 equal rods is:

The correct option is B 20 cm

The correct option is B
20 cm