If the coordinates of A and B be (1, 1) and (5, 7), then the equation of the perpendicular bisector of the line segment AB is

2x+3y=18

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2x-3y+18=0

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2x+3y-1=0

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3x-2y+1=0

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Solution

The correct option is A 2x+3y=18
Mid point is (3, 4)
Slope of perpendicular $= \frac{- 1}{\frac{6}{4}} = \frac{- 2}{3}$
Hence the line is $2 x + 3 y = 18$ .

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If the coordinates of A and B be (1, 1) and (5, 7), then the equation of the perpendicular bisector of the line segment AB is

The correct option is A 2x+3y=18 Mid point is (3, 4) Slope of perpendicular =−164=−23 Hence the line is 2x+3y=18.

The correct option is A 2x+3y=18
Mid point is (3, 4)
Slope of perpendicular $= \frac{- 1}{\frac{6}{4}} = \frac{- 2}{3}$
Hence the line is $2 x + 3 y = 18$ .