Question

If the density of water is $1gc{m}^{-3}$ then the volume occupied by one molecule of water is approximately:

• A. $18c{m}^3$
• B. $22400c{m}^3$
• C. $6.03\times {10}^{-23}c{m}^3$
• D. $3.0\times {10}^{-23}c{m}^3$

Answer 1

Answer: (D)

$3.0\times {10}^{-23}c{m}^3$

$density=\frac{mass}{volume}$
$volume=\frac{mass}{density}$
$=\frac{1gram}{1gramcm⁻³}=1cm³$
$1gwater=\frac{1}{18molesofwater}$
volume occupied by 1 molecules of water =$\frac{18}{(6.02\times 10²³)c{m}^3}$
$=3\times 10⁻²³cm³$
conclusion: hence the option (D) is correct.