Question

If the diagonals of a rhombus are 24 cm and 10 cm, then its perimeter =__________________cm

• A. 48
• B. 52
• C. 60
• D. 80

Answer 1

The correct option is B

52

We know diagonals of a rhombus bisect each other at ${90}^{\circ }$

Let $AC=24cm\therefore AO=OC=12cmBD=10cmBO=OD=5cm$

In $△AOB,A{B}^2={12}^2+5^2$

= ${13}^2$ (5-12-13 Pythagoras Triplet)

$AB=13cm$

Perimeter of rhombus = $4\left(13\right)$

= $52cm$