If the diagonals of a rhombus are 24 cm and 10 cm, then its perimeter =
52
We know diagonals of a rhombus bisect each other at 90∘
Let AC=24cm∴AO=OC=12cmBD=10cmBO=OD=5cm
In △AOB,AB2=122+52
= 132 (5-12-13 Pythagoras Triplet)
AB=13cm
Perimeter of rhombus = 4(13)
= 52cm
Hence (B)