The correct option is C 40
Let the number be ‘x’
35th of the number =3x5
And, 12 of the number =x2
Given: Difference of two numbers = 4
Therefore, 3x5−x2=4
6x−5x10=4
x10=4
If x = 52, LHS =524=13
If x = 48, LHS =484=12
If x = 40, LHS =404=10
If x = 40, LHS = RHS
Hence, the required number is 40.