Question

If the dipole moment of $C{H}_{3}F$ is 1.847 D, the dipole moment of $C{D}_{3}F$ will be

• A. 1.837 D
  
• B. 1.857 D
  
• C. 1.847 D
  
• D. 1.723 D

Answer 1

The correct option is B

1.857 D

The higher dipole moment for $C{D}_{3}F$ is due to higher charge because F pulls electrons from D more easily than from H, i.e., D is more electron-releasing than H.