If the direct transmission method with a cable of resistance 0-4 - km-1 is used- the power dissipation in

The correct option is B 30 R=0.4× 20=8Ω Power loss = loss input × 100 =υ #160; ^ 2 R #160; 600K × 100 = 4000× 4000 600× 1000× 8 × 10 ...

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Standard VIII

Physics

Heating Effect of Electric Current

If the direct...

Question

If the direct transmission method with a cable of resistance $0.4 Ω k m^{- 1}$ is used, the power dissipation (in %) during transmission is

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Solution

The correct option is B 30
$R = 0.4 \times 20 = 8 Ω$
Power loss $= \frac{l o s s}{i n p u t} \times 100$
$= \frac{\frac{υ^{2}}{R}}{600 K} \times 100 = \frac{4000 \times 4000}{600 \times 1000 \times 8} \times 100 = 33.33 \approx 30$

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If the direct transmission method with a cable of resistance 0.4 Ω km−1 is used, the power dissipation (in %) during transmission is

The correct option is B 30R=0.4×20=8ΩPower loss=lossinput×100=υ2R600K×100=4000×4000600×1000×8×100=33.33≈30

If the direct transmission method with a cable of resistance $0.4 Ω k m^{- 1}$ is used, the power dissipation (in %) during transmission is

The correct option is B 30
$R = 0.4 \times 20 = 8 Ω$
Power loss $= \frac{l o s s}{i n p u t} \times 100$
$= \frac{\frac{υ^{2}}{R}}{600 K} \times 100 = \frac{4000 \times 4000}{600 \times 1000 \times 8} \times 100 = 33.33 \approx 30$