Question

If the displacement of simple pendulum at any time is $0.02$$m$ and acceleration is $2m/s^2$, then in this time angular velocity will be:

• A. $100$$rad$/$s$
• B. $10$ $rad$/$s$
• C. $1$ $rad$/$s$
• D. $0.1$ $rad$/$s$

Answer 1

The correct option is B $10$ $rad$/$s$

In a simple pendulum,

$x=x_{0}sin(\omega t+\varphi )$

$⟹a=\frac{d^{2}x}{d{t}^2}=-{\omega }^{2}x$

$⟹\omega =\sqrt{\frac{a}{x}}=\sqrt{\frac{2}{0.02}}$

$=10rad/s$