If the displacement-time graph for the two particles A and B are straight lines inclined at angles of $30^{0}$ and $60^{0}$ with the time axis, then ratio of the velocities $v_{A} : v_{B}$ will be

1:2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1:6

No worries! We‘ve got your back. Try BYJU‘S free classes today!

8:1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1:3

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is B 1:3
$\frac{v_{A}}{v_{B}} = \frac{slope of the curve A}{slope of the curve B}$
$= \frac{tan θ_{A}}{tan θ_{B}}$
$= \frac{tan 30^{o}}{tan 60^{o}}$
$= 1 : 3$

Suggest Corrections

Similar questions

Q. The displacement time graph for two particles A and B are straight lines inclined at angles of

30^{o}

and

60^{0}

with the time axis. The ratio of velocities of

V_{A} : V_{B}

The displacement-time graph for two particles A and B are straight lines inclined at angles of $30^{\circ}$ and $60^{\circ}$ with the time axis. The ratio of velocities of $V_{A}$ : $V_{B}$ is

Q. The displacement time graph for the particles A and B are straight lines inclined at angles

30

degree and

40

degree with the time axis. What is the ratio of the velocities of A and B?

Q. The displacement time graph for two particles

A

and

B

are straight lines inclined at angles of

30^{\circ}

and

60^{\circ}

respectively with the time axis. The ratio

V_{A} ∶ V_{B}

The displacement-time graph for two particles A and B are straight lines inclined at angles of $30^{\circ}$ and $60^{\circ}$ with the time axis. The ratio of velocities of $V_{A}$ : $V_{B}$ is

Join BYJU'S Learning Program

If the displacement-time graph for the two particles A and B are straight lines inclined at angles of 300 and 600 with the time axis, then ratio of the velocities vA:vB will be

The correct option is B 1:3vAvB=slope of the curve Aslope of the curve B =tanθAtanθB =tan30otan60o =1:3

If the displacement-time graph for the two particles A and B are straight lines inclined at angles of $30^{0}$ and $60^{0}$ with the time axis, then ratio of the velocities $v_{A} : v_{B}$ will be

The correct option is B 1:3
$\frac{v_{A}}{v_{B}} = \frac{slope of the curve A}{slope of the curve B}$
$= \frac{tan θ_{A}}{tan θ_{B}}$
$= \frac{tan 30^{o}}{tan 60^{o}}$
$= 1 : 3$