Question

If the distance between $(8,0)$ and A is $7$, then co-ordinates of the point A can not be

• A. $(8,-7)$
• B. $(8,7)$
• C. $(1,0)$
• D. $(0,-8)$

Answer 1

The correct option is D $(0,-8)$

Distance between two points $(x_1,y_1)$ and $(x_2,y_2)$ can be calculated using the formula $\sqrt{{(x_2-x_1)}^2+{(y_2-y_1)}^2}$
We can see that distance between $(8,0)$ and $(0,-8)={(0-8)}^2+{(-8-0)}^2=\sqrt{64+64}=8\sqrt{2}$.
Hence, $A$ cannot be $(0,-8)$