Question

IF the distance between (8,0) and A is 7, then coordinates of the point A can not be

• A. (8-7)
• B. (8,7)
• C. (1,0)
• D. (0,-8)

Answer 1

The correct option is D (0,-8)

We know that the distance between two points

$=\sqrt{(x_2-x_1{)}^2+(y_2-y_1{)}^2}$

Since, the distance between the point $(8,0)$ and $A$ is $7$.

Therefore,

Option $A$

$=\sqrt{(8-8{)}^2+(-7-0{)}^2}=7$

Option $B$

$=\sqrt{(8-8{)}^2+(7-0{)}^2}=7$

Option $C$

$=\sqrt{(8-1{)}^2+(0-0{)}^2}=7$

Option $D$

$=\sqrt{(8-0{)}^2+(0-8{)}^2}=8\sqrt{2}$

So, point $A$ can not be $(0,-8)$.

Hence, this is the answer.