Question

If the distance between points P (x, 2) and Q (3, –­6) is 10 units, then x =

• A. 3
• B. -3
• C. 9
• D. -9

Answer 1

Answer: (B), (C)

The correct options are
B

-3

C

9

PQ = $\sqrt{(3-x{)}^2+(-6-\left(2\right){)}^2}=10$
$(3-x{)}^2+(6+2{)}^2=100$
$(3-x{)}^2=36$
$3-x=\pm 6$
$x=-3$ or $x=9$