If the distance between the points P (x, 2) and Q (3, –6) is 10 units, then x = _____.

No worries! We‘ve got your back. Try BYJU‘S free classes today!

-3

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C
9

Distance between the points $(x_{1}, y_{1}) and (x_{2}, y_{2})$ is given by
$\sqrt{(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}}$

$∴ P Q = \sqrt{(3 - x)^{2} + (- 6 - 2)^{2}} = 10 (3 - x)^{2} + (8)^{2} = 100 (3 - x)^{2} + 64 = 100 (3 - x)^{2} = 36 3 - x = \pm 6 x = - 3 or 9$

Suggest Corrections

Similar questions

If the distance between points P (x, 2) and Q (3, 6) is 10 units, then x =

If x is a positive integer such that the distance between points P (x, 2) and Q (3, –6) is 10 units, then x =

Find the value of $y$ if the distance between the points $A (2, - 3)$ & $B (10, y)$ is $10$ units.

Join BYJU'S Learning Program