Question

If the electron in a hydrogen atom jumps from an orbit level $n_1=3$ to an orbit level $n_2=2$, the emitted radiation has a wavelength given by

• A. $\lambda =\frac{36}{5R}$
• B. $\lambda =\frac{5R}{36}$
• C. $\lambda =\frac{6}{R}$
• D. $\lambda =\frac{R}{6}$

Answer 1

Answer: (A)

$\lambda =\frac{36}{5R}$

According to formula wave number:
$\overline{v}=R[\frac{1}{n{{}_1}^2}-\frac{1}{n{{}_2}^2}]$
$\lambda =\frac{1}{R[\frac{1}{4}-\frac{1}{9}]}$
$\Rightarrow \lambda =\frac{36}{5R}$