Question

If the electron in an hydrogen atom jumps from an orbit with level $n_f=3$ to an orbit with level $n_f=2$, the emitted radiation has a wavelength given by

• A. $\lambda =\frac{R}{6}$
• B. $\lambda =\frac{36}{5R}$
• C. $\lambda =\frac{6}{R}$
• D. $\lambda =\frac{5R}{36}$

Answer 1

The correct option is B $\lambda =\frac{36}{5R}$

Therefore, $\frac{1}{\lambda }=R(\frac{1}{4}-\frac{1}{9})=\frac{5R}{36}\therefore \lambda =\frac{36}{5R}$