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Non-Ideal Battery

If the emf of...

Question

If the emf of the battery in primary circuit of a potetimeter is doubled the value of potential gradient will:-

Remain Uncharged

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Be halved

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Be doubled

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None of these

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Solution

The correct option is C Be doubled
$\begin{matrix} P . G = (\frac{E}{R + R_{w}}) \frac{R_{w}}{l_{w}} T h e n, I f E i s d o u b l e t h e n p o t e n t i a l g r a d i e n t i s a l s o d o u b l e . H e n c e, o p t i o n C i s t h e c o r r e c t a n s w e r . \end{matrix}$

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