Question

If the energy of a capacitor of capacitance $2\mu F$ is 0.16 joule, then its potential difference will be:

• A. $800V$
• B. $400V$
• C. $16\times {10}^{4}V$
• D. $6\times {10}^{2}V$

Answer 1

The correct option is B $400V$

Here, Energy of a capacita = $\frac{1}{2}c{v}^2$

$0.16j=\frac{1}{2}c{v}^2$

$0.16j=\frac{1}{2}\times 2\times {10}^{-6}v$

$0.16\times {10}^{6}vdt=V^2$

V = 400 Volt

Hence option (B) is correct