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Question

If the energy of incident radiation is doubled, how will the maximum kinetic energy of the photoelectrons change?

A
becomes double
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B
becomes more than double
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C
becomes half
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D
doesn't change
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Solution

The correct option is B becomes more than double

Let say
(K.E)max1=Eϕ0.....(1)
If the energy of incident radiation is doubled,
(K.E)max2=2Eϕ0
=E+(Eϕ0)
K.Emax2=E+K.Emax1 ---from (1)
As, E>K.Emax1
K.Emax2>2K.Emax1

Hence, (B) is the correct answer.

Why this question?
The question tests thorough understanding of the formula, corresponding manipulation and predictions of the same.

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