Question

If the energy of photons corresponding to wavelength of $6000\stackrel{o}{A}$ is $3.2\times {10}^{-19}$J. The photon energy for wavelength of $4000\stackrel{o}{A}$ will be ___________.

• A. $4.44\times {10}^{-19}$J
• B. $2.22\times {10}^{-19}$J
• C. $1.11\times {10}^{-19}$J
• D. $4.80\times {10}^{-19}$J

Answer 1

The correct option is D $4.80\times {10}^{-19}$J

Energy of the photon $E=\frac{hc}{\lambda }$
$⟹$ $\frac{E_2}{E_1}=\frac{{\lambda }_1}{{\lambda }_2}$
Given : ${\lambda }_1=6000A^o$ $E_1=3.2\times {10}^{-19}J$ ${\lambda }_2=4000A^o$
$\therefore$ $\frac{E_2}{3.2\times {10}^{-19}}=\frac{6000}{4000}$
We get $E_2=4.80\times {10}^{-19}J$
So, correct answer is option D.