If the equation x2+y2=2x is written in polar coordinate system, then r can be
A
0
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B
1
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C
2cosθ
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D
2sinθ
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Solution
The correct option is C2cosθ Since, we know that x=rcosθ,y=rsinθ
Now putting this in the given equation, we have x2+y2=2x ⇒r2cos2θ+r2sin2θ=2rcosθ ⇒r2(sin2θ+cos2θ)=2rcosθ ⇒r2=2rcosθ ⇒r(r−2cosθ)=0 ⇒r=0 or r=2cosθ