If the equations x2−kx−21=0 and x2−3kx+35=0 have a common root α<0, then the value of k is
A
−7
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B
4
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C
7
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D
−4
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Solution
The correct option is D−4 Let α be the common root.
Then, α2−kα−21=0⋯(1)
and α2−3kα+35=0⋯(2)
Subtracting (1) and (2), we get 2kα−56=0 ⇒kα=28⋯(3)
Putting kα=28 in (1), α2−28−21=0 ⇒α=−7(∵α<0)
From (3), we have kα=28⇒k=−4