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Question

If the expression [mx1+1x] is non-negative for all real x, then the minimum value of m must be

A
12
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B
0
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C
14
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D
12
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Solution

The correct option is C 14
f(x)=mx1+1xf(x)=mx2x+1xf(x)0
for every xR.(1)24m04m1m14
minimum value of m is 14.

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