If the first term of an AP is 3 and the common difference is 5, the $n^{t h}$ term of the AP is .

5 n - 2

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3 n + 4

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3 n - 4

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5 n + 2

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Solution

The correct option is A $5 n - 2$
$a_{n} = a + (n - 1) d$
where
a = first term
d = common difference
$a_{n} = n^{t h} t e r m$
Given, a = 3, d = 5
$a_{n} = 3 + (n - 1) 5$
$a_{n} = 3 + 5 n - 5$
$a_{n} = 5 n - 2$

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